Integrand size = 26, antiderivative size = 121 \[ \int \frac {(e+f x)^n}{(a+b x)^{3/2} \sqrt {c+d x}} \, dx=-\frac {2 \sqrt {\frac {b (c+d x)}{b c-a d}} (e+f x)^n \left (\frac {b (e+f x)}{b e-a f}\right )^{-n} \operatorname {AppellF1}\left (-\frac {1}{2},\frac {1}{2},-n,\frac {1}{2},-\frac {d (a+b x)}{b c-a d},-\frac {f (a+b x)}{b e-a f}\right )}{b \sqrt {a+b x} \sqrt {c+d x}} \]
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Time = 0.06 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {145, 144, 143} \[ \int \frac {(e+f x)^n}{(a+b x)^{3/2} \sqrt {c+d x}} \, dx=-\frac {2 (e+f x)^n \sqrt {\frac {b (c+d x)}{b c-a d}} \left (\frac {b (e+f x)}{b e-a f}\right )^{-n} \operatorname {AppellF1}\left (-\frac {1}{2},\frac {1}{2},-n,\frac {1}{2},-\frac {d (a+b x)}{b c-a d},-\frac {f (a+b x)}{b e-a f}\right )}{b \sqrt {a+b x} \sqrt {c+d x}} \]
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Rule 143
Rule 144
Rule 145
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {\frac {b (c+d x)}{b c-a d}} \int \frac {(e+f x)^n}{(a+b x)^{3/2} \sqrt {\frac {b c}{b c-a d}+\frac {b d x}{b c-a d}}} \, dx}{\sqrt {c+d x}} \\ & = \frac {\left (\sqrt {\frac {b (c+d x)}{b c-a d}} (e+f x)^n \left (\frac {b (e+f x)}{b e-a f}\right )^{-n}\right ) \int \frac {\left (\frac {b e}{b e-a f}+\frac {b f x}{b e-a f}\right )^n}{(a+b x)^{3/2} \sqrt {\frac {b c}{b c-a d}+\frac {b d x}{b c-a d}}} \, dx}{\sqrt {c+d x}} \\ & = -\frac {2 \sqrt {\frac {b (c+d x)}{b c-a d}} (e+f x)^n \left (\frac {b (e+f x)}{b e-a f}\right )^{-n} F_1\left (-\frac {1}{2};\frac {1}{2},-n;\frac {1}{2};-\frac {d (a+b x)}{b c-a d},-\frac {f (a+b x)}{b e-a f}\right )}{b \sqrt {a+b x} \sqrt {c+d x}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(262\) vs. \(2(121)=242\).
Time = 2.19 (sec) , antiderivative size = 262, normalized size of antiderivative = 2.17 \[ \int \frac {(e+f x)^n}{(a+b x)^{3/2} \sqrt {c+d x}} \, dx=\frac {2 \sqrt {c+d x} (e+f x)^n \left (\frac {b (e+f x)}{b e-a f}\right )^{-n} \left (-3 (b c-a d)^2 \operatorname {AppellF1}\left (-\frac {1}{2},-\frac {1}{2},-n,\frac {1}{2},\frac {d (a+b x)}{-b c+a d},\frac {f (a+b x)}{-b e+a f}\right )+3 d (-b c+a d) (a+b x) \operatorname {AppellF1}\left (\frac {1}{2},-\frac {1}{2},-n,\frac {3}{2},\frac {d (a+b x)}{-b c+a d},\frac {f (a+b x)}{-b e+a f}\right )+d^2 (a+b x)^2 \operatorname {AppellF1}\left (\frac {3}{2},\frac {1}{2},-n,\frac {5}{2},\frac {d (a+b x)}{-b c+a d},\frac {f (a+b x)}{-b e+a f}\right )\right )}{3 (b c-a d)^3 \sqrt {a+b x} \sqrt {\frac {b (c+d x)}{b c-a d}}} \]
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\[\int \frac {\left (f x +e \right )^{n}}{\left (b x +a \right )^{\frac {3}{2}} \sqrt {d x +c}}d x\]
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\[ \int \frac {(e+f x)^n}{(a+b x)^{3/2} \sqrt {c+d x}} \, dx=\int { \frac {{\left (f x + e\right )}^{n}}{{\left (b x + a\right )}^{\frac {3}{2}} \sqrt {d x + c}} \,d x } \]
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\[ \int \frac {(e+f x)^n}{(a+b x)^{3/2} \sqrt {c+d x}} \, dx=\int \frac {\left (e + f x\right )^{n}}{\left (a + b x\right )^{\frac {3}{2}} \sqrt {c + d x}}\, dx \]
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\[ \int \frac {(e+f x)^n}{(a+b x)^{3/2} \sqrt {c+d x}} \, dx=\int { \frac {{\left (f x + e\right )}^{n}}{{\left (b x + a\right )}^{\frac {3}{2}} \sqrt {d x + c}} \,d x } \]
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\[ \int \frac {(e+f x)^n}{(a+b x)^{3/2} \sqrt {c+d x}} \, dx=\int { \frac {{\left (f x + e\right )}^{n}}{{\left (b x + a\right )}^{\frac {3}{2}} \sqrt {d x + c}} \,d x } \]
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Timed out. \[ \int \frac {(e+f x)^n}{(a+b x)^{3/2} \sqrt {c+d x}} \, dx=\int \frac {{\left (e+f\,x\right )}^n}{{\left (a+b\,x\right )}^{3/2}\,\sqrt {c+d\,x}} \,d x \]
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